4a^2-10a-6=0

Solution for 4a^2-10a-6=0 equation:

4a^2-10a-6=0

a = 4; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·4·(-6)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*4}=\frac{-4}{8}
=-1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*4}=\frac{24}{8}
=3
$